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#include |
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3
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#include "ptypes.h" |
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4
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#include "rational.h" |
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5
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#define FUNC_gcd_ui 1 |
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6
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#include "util.h" |
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7
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#include "totients.h" |
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8
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9
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10
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351
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int contfrac(UV** cfrac, UV *rem, UV num, UV den) |
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11
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{ |
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12
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UV *cf; |
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13
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351
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int steps = 0; |
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14
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351
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New(0, cf, 2 * BITS_PER_WORD, UV); /* Upper limit for gcd steps */ |
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15
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1824
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100
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while (den > 0) { |
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16
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1473
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UV q = num/den; |
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17
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1473
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UV r = num - q*den; |
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18
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1473
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num = den; |
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19
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1473
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den = r; |
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20
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1473
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cf[steps++] = q; |
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21
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} |
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22
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351
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*rem = num; |
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23
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351
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*cfrac = cf; |
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24
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351
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return steps; |
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25
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} |
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26
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27
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99
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bool next_calkin_wilf(UV* num, UV* den) |
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28
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{ |
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29
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UV n, d; |
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30
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99
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50
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if (num == 0 || den == 0) return 0; |
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50
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31
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99
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n = *num; |
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32
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99
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d = *den; |
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33
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99
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50
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if (n == 0 || d == 0 || gcd_ui(n,d) != 1) return 0; |
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50
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50
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34
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35
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/* next = d / (n+d-2*(n%d)) = d / (2(n/d)+1)*d-n */ |
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36
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99
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100
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if (n < d) { /* n/d is 0 */ |
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37
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49
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*den = d-n; |
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38
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50
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100
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} else if (d == 1) { |
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39
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6
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50
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if (n == UV_MAX) return 0; |
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40
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6
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*den = n + 1; |
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41
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} else { /* n >= d and d >= 2 */ |
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42
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44
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UV nd = n % d; /* nd is less than d and less than n */ |
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43
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44
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UV nr = n-nd, dr = d-nd; |
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44
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44
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50
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if (nr > UV_MAX-dr) return 0; |
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45
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44
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*den = nr + dr; |
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46
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} |
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47
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99
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*num = d; |
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48
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99
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return 1; |
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49
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} |
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50
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99
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bool next_stern_brocot(UV* num, UV* den) |
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51
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{ |
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52
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UV n, d; |
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53
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99
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50
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if (num == 0 || den == 0) return 0; |
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50
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54
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99
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n = *num; |
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55
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99
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d = *den; |
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56
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99
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50
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if (n == 0 || d == 0 || gcd_ui(n,d) != 1) return 0; |
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50
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50
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57
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58
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/* Backhouse and Ferreira show how to do this *if* we had a 2x2 matrix |
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59
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* for the node. We could also exploit that given a/b and the next c/d |
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60
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* bc-ad=3 if they share a parent |
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61
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* but this doesn't give us enough information to solve for both c,d. |
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62
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*/ |
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63
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64
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99
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100
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if (*den == 1) { /* At end of the row, go to the start of the next. */ |
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65
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6
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50
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if (*num == UV_MAX) return 0; |
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66
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6
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*den = *num+1; |
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67
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6
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*num = 1; |
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68
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6
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return 1; |
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69
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} |
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70
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/* Given the tree e.g. LLLRRLLRR, we can go up to the nearest ancestor, |
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71
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* then back down. That is, from the right, invert all L/R from the end |
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72
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* to and including the right L. This really isn't a huge savings over |
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73
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* doing the full process. Doing nth(n(F)+1) is clean. */ |
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74
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93
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return nth_stern_brocot(num, den, 1+stern_brocot_n(*num, *den)); |
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75
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} |
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76
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77
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78
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#if 0 /* A recursive version */ |
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79
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UV calkin_wilf_n(UV num, UV den) |
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80
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{ |
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81
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if (num == den) { |
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82
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return 1; |
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83
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} else if (num > den) { |
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84
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UV f = calkin_wilf_n(num-den, num); |
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85
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if (f == 0 || f == UV_MAX) return 0; |
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86
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return 1 + f; |
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87
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} else { |
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88
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UV f = calkin_wilf_n(num, den-num); |
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89
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if (f == 0 || f > (UV_MAX/2)) return 0; |
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90
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return 2 * f; |
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91
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} |
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92
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} |
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93
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#endif |
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94
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95
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313
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UV calkin_wilf_n(UV num, UV den) |
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96
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{ |
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97
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313
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UV *cf = 0, n = 0, rem; |
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98
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313
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uint32_t bit, d = 1, shift = 0; |
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99
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313
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int i, steps = contfrac(&cf, &rem, num, den); |
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100
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101
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313
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50
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if (rem != 1) croak("Rational must be reduced"); |
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102
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313
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50
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if (steps == 0) return 0; |
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103
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104
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313
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cf[steps-1]--; |
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105
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1494
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100
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for (i = 0; i < steps; i++) { |
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106
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1187
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100
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if ((shift+cf[i]) >= BITS_PER_WORD) |
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107
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6
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break; |
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108
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1181
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100
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if (d) |
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109
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1606
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100
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for (bit = 0; bit < cf[i]; bit++) |
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110
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944
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n |= UVCONST(1) << (shift+bit); |
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111
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1181
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shift += cf[i]; |
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112
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1181
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d ^= 1; /* d = 1-d; */ |
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113
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} |
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114
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313
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Safefree(cf); |
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115
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313
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100
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if (i < steps) return 0; |
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116
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307
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n |= UVCONST(1) << shift; |
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117
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307
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return n; |
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118
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} |
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119
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203
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UV stern_brocot_n(UV num, UV den) |
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120
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{ |
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121
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/* Reverse bits in the Calkin-Wilf n */ |
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122
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203
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UV n, M = calkin_wilf_n(num,den); |
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123
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203
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100
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if (M == 0) return 0; |
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124
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1294
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100
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for (n = 1; M > 1; M >>= 1) |
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125
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1094
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n = (n << 1) | (M & 1); |
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126
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200
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return n; |
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127
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} |
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128
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129
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130
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107
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bool nth_calkin_wilf(UV* num, UV* den, UV n) |
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131
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{ |
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132
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107
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uint32_t b = 1; |
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133
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107
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UV p = 0, q = 1; /* p odd q even */ |
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134
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742
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100
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{ UV v = n; while (v >>= 1) b++; } |
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135
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849
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100
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while (b--) { |
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136
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742
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100
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if ((n >> b) & 1) p += q; |
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137
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292
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else q += p; |
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138
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} |
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139
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107
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*num = p; |
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140
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107
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*den = q; |
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141
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107
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return 1; |
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142
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} |
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143
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200
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bool nth_stern_brocot(UV* num, UV* den, UV n) |
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144
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{ |
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145
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200
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UV p = 1, q = 1; /* p odd q even */ |
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146
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1294
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100
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while (n > 1) { |
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147
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1094
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100
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if (n & 1) p += q; |
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148
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532
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else q += p; |
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149
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1094
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n >>= 1; |
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150
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} |
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151
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200
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*num = p; |
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152
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200
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*den = q; |
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153
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200
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return 1; |
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154
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} |
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155
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156
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340
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UV nth_stern_diatomic(UV n) |
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157
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{ |
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158
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340
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UV p = 0, q = 1; |
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159
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2455
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100
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while (n) { |
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160
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2115
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100
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if (n & 1) p += q; |
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161
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983
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else q += p; |
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162
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2115
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n >>= 1; |
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163
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} |
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164
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340
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return p; |
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165
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} |
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166
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167
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168
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169
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34
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UV farey_length(uint32_t n) |
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170
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{ |
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171
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34
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UV t = sumtotient(n); |
|
172
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34
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50
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return (t == 0) ? 0 : 1 + sumtotient(n); |
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173
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} |
|
174
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175
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939
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bool next_farey(uint32_t n, uint32_t* p, uint32_t* q) |
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176
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{ |
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177
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IV ivu, ivg; |
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178
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UV u, uvp, uvq; |
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179
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180
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939
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50
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if (n == 0 || p == 0 || q == 0 || *p >= *q) return 0; |
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50
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50
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50
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181
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182
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939
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ivg = gcdext( (IV)*p, (IV)*q, &ivu, 0, 0, 0); |
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183
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184
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939
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u = ivu; |
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185
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939
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uvp = *p / ivg; |
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186
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939
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uvq = *q / ivg; |
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187
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188
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939
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*q = ((n+u) / uvq) * uvq - u; |
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189
|
939
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*p = (*q * uvp + 1) / uvq; |
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190
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939
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return 1; |
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191
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} |
|
192
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193
|
10
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UV farey_array(uint32_t n, uint32_t **rnum, uint32_t **rden) |
|
194
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|
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{ |
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195
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uint32_t *num, *den; |
|
196
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10
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UV i, j, p0 = 0, q0 = 1, p1 = 1, q1 = n, p2, q2; |
|
197
|
10
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|
UV len = farey_length(n); |
|
198
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|
199
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10
|
50
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|
if (n < 1 || len < 2 || len >= UVCONST(4294967295)) |
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|
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50
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50
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|
200
|
0
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return 0; |
|
201
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|
202
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10
|
50
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New(0, num, len, uint32_t); |
|
203
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10
|
50
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New(0, den, len, uint32_t); |
|
204
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205
|
124
|
100
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for (i = 0; i < len; i++) { |
|
206
|
114
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|
num[i] = p0; |
|
207
|
114
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|
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|
|
den[i] = q0; |
|
208
|
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|
/* Haros (1802), gives p/q using two previous terms */ |
|
209
|
114
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|
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|
|
j = (q0 + n) / q1; |
|
210
|
114
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|
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|
|
p2 = j * p1 - p0; |
|
211
|
114
|
|
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|
q2 = j * q1 - q0; |
|
212
|
114
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|
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|
p0 = p1; q0 = q1; p1 = p2; q1 = q2; |
|
213
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|
} |
|
214
|
10
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|
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|
*rnum = num; |
|
215
|
10
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|
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|
*rden = den; |
|
216
|
10
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|
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|
return len; |
|
217
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|
} |
|
218
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219
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|
220
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221
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/* |
|
222
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* See: |
|
223
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* Pătraşcu and Pătraşcu (ANTS 2004) |
|
224
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* https://citeseerx.ist.psu.edu/document?repid=rep1&type=pdf&doi=d8882e782674d5cd312129823287768e123674e1 |
|
225
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|
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* |
|
226
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* Pawlewicz (2007) |
|
227
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|
* https://www.mimuw.edu.pl/~pan/papers/farey-esa.pdf |
|
228
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* |
|
229
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* Pawlewicz and Pătraşcu (2008) |
|
230
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* https://www.researchgate.net/publication/225715205_Order_Statistics_in_the_Farey_Sequences_in_Sublinear_Time_and_Counting_Primitive_Lattice_Points_in_Polygons |
|
231
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|
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* |
|
232
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* For the rank, we're using a very simple but fast version. |
|
233
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|
* TODO: Use the method from Pawlewicz 2007 (see page 7). |
|
234
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|
* |
|
235
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|
* For the kth member, binary search on rank. |
|
236
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|
*/ |
|
237
|
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|
238
|
346
|
|
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|
UV farey_rank(uint32_t n, uint32_t p, uint32_t q) |
|
239
|
|
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|
|
{ |
|
240
|
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|
|
uint32_t *count, i, g; |
|
241
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|
UV sum; |
|
242
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|
243
|
346
|
50
|
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|
|
if (n == 0 || q == 0 || p == 0) return 0; |
|
|
|
50
|
|
|
|
|
|
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|
|
100
|
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|
244
|
|
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|
245
|
335
|
|
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|
|
|
g = gcd_ui(p,q); |
|
246
|
335
|
100
|
|
|
|
|
if (g != 1) { p /= g; q /= g; } |
|
247
|
|
|
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|
|
|
|
|
248
|
335
|
|
|
|
|
|
New(0, count, n+1, uint32_t); |
|
249
|
|
|
|
|
|
|
|
|
250
|
8777
|
100
|
|
|
|
|
for (i = 2; i <= n; i++) |
|
251
|
8442
|
|
|
|
|
|
count[i] = ((UV)i * p - 1) / q; |
|
252
|
335
|
|
|
|
|
|
sum = 1; |
|
253
|
8777
|
100
|
|
|
|
|
for (i = 2; i <= n; i++) { |
|
254
|
8442
|
|
|
|
|
|
uint32_t j, icount = count[i]; |
|
255
|
36831
|
100
|
|
|
|
|
for (j = i; j <= n-i; j += i) |
|
256
|
28389
|
|
|
|
|
|
count[j+i] -= icount; |
|
257
|
8442
|
|
|
|
|
|
sum += icount; |
|
258
|
|
|
|
|
|
|
} |
|
259
|
335
|
|
|
|
|
|
Safefree(count); |
|
260
|
335
|
|
|
|
|
|
return sum; |
|
261
|
|
|
|
|
|
|
} |
|
262
|
|
|
|
|
|
|
|
|
263
|
|
|
|
|
|
|
|
|
264
|
|
|
|
|
|
|
#if 0 /* Naive method. */ |
|
265
|
|
|
|
|
|
|
int kth_farey(uint32_t n, UV k, uint32_t* p, uint32_t* q) |
|
266
|
|
|
|
|
|
|
{ |
|
267
|
|
|
|
|
|
|
UV i, j, p0 = 0, q0 = 1, p1 = 1, q1 = n, p2, q2; |
|
268
|
|
|
|
|
|
|
UV len = farey_length(n); |
|
269
|
|
|
|
|
|
|
|
|
270
|
|
|
|
|
|
|
if (n > 0 && len < 2) return -1; /* overflow */ |
|
271
|
|
|
|
|
|
|
if (n == 0 || k >= len) return 0; /* undefined */ |
|
272
|
|
|
|
|
|
|
|
|
273
|
|
|
|
|
|
|
if (k > len/2) { /* Exploit symmetry about 1/2, iterate backwards */ |
|
274
|
|
|
|
|
|
|
p0 = 1; |
|
275
|
|
|
|
|
|
|
p1 = n-1; |
|
276
|
|
|
|
|
|
|
k = (len-1)-k; |
|
277
|
|
|
|
|
|
|
} |
|
278
|
|
|
|
|
|
|
for (i = 0; i < k; i++) { |
|
279
|
|
|
|
|
|
|
j = (q0 + n) / q1; |
|
280
|
|
|
|
|
|
|
p2 = j * p1 - p0; |
|
281
|
|
|
|
|
|
|
q2 = j * q1 - q0; |
|
282
|
|
|
|
|
|
|
p0 = p1; q0 = q1; p1 = p2; q1 = q2; |
|
283
|
|
|
|
|
|
|
} |
|
284
|
|
|
|
|
|
|
*p = p0; *q = q0; |
|
285
|
|
|
|
|
|
|
return 1; |
|
286
|
|
|
|
|
|
|
} |
|
287
|
|
|
|
|
|
|
#else |
|
288
|
90
|
|
|
|
|
|
static bool _walk_to_k(uint32_t a, uint32_t n, uint32_t k, uint32_t* p, uint32_t* q) |
|
289
|
|
|
|
|
|
|
{ |
|
290
|
|
|
|
|
|
|
uint32_t g, j, p0, q0, p1, q1, p2, q2; |
|
291
|
|
|
|
|
|
|
|
|
292
|
90
|
|
|
|
|
|
g = gcd_ui(a,n); |
|
293
|
90
|
|
|
|
|
|
p0 = a/g; |
|
294
|
90
|
|
|
|
|
|
q0 = n/g; |
|
295
|
|
|
|
|
|
|
|
|
296
|
90
|
100
|
|
|
|
|
if (k == 0) { *p = p0; *q = q0; return 1; } |
|
297
|
|
|
|
|
|
|
|
|
298
|
|
|
|
|
|
|
/* From the single point, use extgcd to get the exact next fraction */ |
|
299
|
62
|
|
|
|
|
|
p1 = p0; q1 = q0; |
|
300
|
62
|
|
|
|
|
|
next_farey(n, &p1, &q1); |
|
301
|
|
|
|
|
|
|
|
|
302
|
|
|
|
|
|
|
/* Now we have two fractions, so quick step through */ |
|
303
|
145
|
100
|
|
|
|
|
while (--k) { |
|
304
|
83
|
|
|
|
|
|
j = (q0 + n) / q1; |
|
305
|
83
|
|
|
|
|
|
p2 = j * p1 - p0; |
|
306
|
83
|
|
|
|
|
|
q2 = j * q1 - q0; |
|
307
|
83
|
|
|
|
|
|
p0 = p1; p1 = p2; q0 = q1; q1 = q2; |
|
308
|
|
|
|
|
|
|
} |
|
309
|
62
|
|
|
|
|
|
*p = p1; |
|
310
|
62
|
|
|
|
|
|
*q = q1; |
|
311
|
62
|
|
|
|
|
|
return 1; |
|
312
|
|
|
|
|
|
|
} |
|
313
|
128
|
|
|
|
|
|
bool kth_farey(uint32_t n, UV k, uint32_t* p, uint32_t* q) |
|
314
|
|
|
|
|
|
|
{ |
|
315
|
128
|
|
|
|
|
|
uint32_t lo = 1, hi = n; |
|
316
|
128
|
|
|
|
|
|
UV cnt = 1; |
|
317
|
|
|
|
|
|
|
|
|
318
|
128
|
100
|
|
|
|
|
if (k < 2) { |
|
319
|
20
|
100
|
|
|
|
|
if (k == 0) { *p = 0; *q = 1; } |
|
320
|
10
|
|
|
|
|
|
else { *p = 1; *q = n; } |
|
321
|
20
|
|
|
|
|
|
return 1; |
|
322
|
|
|
|
|
|
|
} |
|
323
|
108
|
100
|
|
|
|
|
if (n < 2) return 0; |
|
324
|
|
|
|
|
|
|
|
|
325
|
|
|
|
|
|
|
/* For a substantial performance benefit, we will estimate the position |
|
326
|
|
|
|
|
|
|
* and get its rank. Then look a small distance in the other direction. |
|
327
|
|
|
|
|
|
|
* For small n this often completely brackets the value after only one |
|
328
|
|
|
|
|
|
|
* or two calls. For large n, we can often do 2-5 times fewer calls. |
|
329
|
|
|
|
|
|
|
* |
|
330
|
|
|
|
|
|
|
* The downside is this is ugly, but it makes this call 2-4x faster. |
|
331
|
|
|
|
|
|
|
*/ |
|
332
|
107
|
100
|
|
|
|
|
if (n >= 5) { |
|
333
|
95
|
|
|
|
|
|
uint32_t const ginc = ((UV)n+8191)>>13; |
|
334
|
95
|
|
|
|
|
|
double const dlen = 1 + (0.304*(double)n*n + .29*(double)n + 0.95); |
|
335
|
95
|
|
|
|
|
|
uint32_t guess = k * ((double)n/dlen); |
|
336
|
95
|
|
|
|
|
|
UV gcnt = 0; |
|
337
|
95
|
100
|
|
|
|
|
if (guess <= lo) guess = lo+1; else if (guess >= hi) guess = hi-1; |
|
|
|
100
|
|
|
|
|
|
|
338
|
|
|
|
|
|
|
|
|
339
|
95
|
50
|
|
|
|
|
if (lo < hi) { |
|
340
|
95
|
|
|
|
|
|
gcnt = farey_rank(n, guess, n); |
|
341
|
95
|
100
|
|
|
|
|
if (gcnt <= k) { lo = guess; cnt = gcnt; } else { hi = guess-1; } |
|
342
|
|
|
|
|
|
|
} |
|
343
|
|
|
|
|
|
|
|
|
344
|
|
|
|
|
|
|
/* Look a small distance in the other direction. We want it to be |
|
345
|
|
|
|
|
|
|
* far enough that we bracket the value, but not so far that we make |
|
346
|
|
|
|
|
|
|
* too many calls getting back. */ |
|
347
|
95
|
100
|
|
|
|
|
if (gcnt <= k) { guess = (hi-ginc < guess) ? hi : guess+ginc; } |
|
|
|
50
|
|
|
|
|
|
|
348
|
15
|
100
|
|
|
|
|
else { guess = (lo+ginc+1 > guess) ? lo : guess-1-ginc; } |
|
349
|
|
|
|
|
|
|
|
|
350
|
95
|
100
|
|
|
|
|
if (lo < hi && guess > lo && guess < hi) { |
|
|
|
50
|
|
|
|
|
|
|
|
|
100
|
|
|
|
|
|
|
351
|
67
|
|
|
|
|
|
gcnt = farey_rank(n,guess,n); |
|
352
|
67
|
100
|
|
|
|
|
if (gcnt <= k) { lo = guess; cnt = gcnt; } else { hi = guess-1; } |
|
353
|
|
|
|
|
|
|
} |
|
354
|
|
|
|
|
|
|
} |
|
355
|
|
|
|
|
|
|
|
|
356
|
|
|
|
|
|
|
/* Now the binary search. */ |
|
357
|
|
|
|
|
|
|
|
|
358
|
181
|
100
|
|
|
|
|
while (lo < hi) { |
|
359
|
74
|
|
|
|
|
|
uint32_t mid = lo + ((hi-lo+1)>>1); |
|
360
|
74
|
|
|
|
|
|
UV midcnt = farey_rank(n, mid, n); |
|
361
|
74
|
100
|
|
|
|
|
if (midcnt <= k) { lo = mid; cnt = midcnt; } |
|
362
|
48
|
|
|
|
|
|
else { hi = mid-1; } |
|
363
|
|
|
|
|
|
|
} |
|
364
|
107
|
100
|
|
|
|
|
if (lo == n) { |
|
365
|
17
|
|
|
|
|
|
*p = (cnt == k); |
|
366
|
17
|
|
|
|
|
|
*q = 1; |
|
367
|
17
|
|
|
|
|
|
return k <= cnt; |
|
368
|
|
|
|
|
|
|
} |
|
369
|
90
|
|
|
|
|
|
return _walk_to_k(lo, n, k-cnt, p, q); |
|
370
|
|
|
|
|
|
|
} |
|
371
|
|
|
|
|
|
|
#endif |