File Coverage

src/rsa/rsa_i15_keygen.c
Criterion Covered Total %
statement 0 201 0.0
branch 0 84 0.0
condition n/a
subroutine n/a
pod n/a
total 0 285 0.0


line stmt bran cond sub pod time code
1             /*
2             * Copyright (c) 2018 Thomas Pornin
3             *
4             * Permission is hereby granted, free of charge, to any person obtaining
5             * a copy of this software and associated documentation files (the
6             * "Software"), to deal in the Software without restriction, including
7             * without limitation the rights to use, copy, modify, merge, publish,
8             * distribute, sublicense, and/or sell copies of the Software, and to
9             * permit persons to whom the Software is furnished to do so, subject to
10             * the following conditions:
11             *
12             * The above copyright notice and this permission notice shall be
13             * included in all copies or substantial portions of the Software.
14             *
15             * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND,
16             * EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
17             * MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
18             * NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS
19             * BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN
20             * ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN
21             * CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
22             * SOFTWARE.
23             */
24              
25             #include "inner.h"
26              
27             /*
28             * Make a random integer of the provided size. The size is encoded.
29             * The header word is untouched.
30             */
31             static void
32 0           mkrand(const br_prng_class **rng, uint16_t *x, uint32_t esize)
33             {
34             size_t u, len;
35             unsigned m;
36              
37 0           len = (esize + 15) >> 4;
38 0           (*rng)->generate(rng, x + 1, len * sizeof(uint16_t));
39 0 0         for (u = 1; u < len; u ++) {
40 0           x[u] &= 0x7FFF;
41             }
42 0           m = esize & 15;
43 0 0         if (m == 0) {
44 0           x[len] &= 0x7FFF;
45             } else {
46 0           x[len] &= 0x7FFF >> (15 - m);
47             }
48 0           }
49              
50             /*
51             * This is the big-endian unsigned representation of the product of
52             * all small primes from 13 to 1481.
53             */
54             static const unsigned char SMALL_PRIMES[] = {
55             0x2E, 0xAB, 0x92, 0xD1, 0x8B, 0x12, 0x47, 0x31, 0x54, 0x0A,
56             0x99, 0x5D, 0x25, 0x5E, 0xE2, 0x14, 0x96, 0x29, 0x1E, 0xB7,
57             0x78, 0x70, 0xCC, 0x1F, 0xA5, 0xAB, 0x8D, 0x72, 0x11, 0x37,
58             0xFB, 0xD8, 0x1E, 0x3F, 0x5B, 0x34, 0x30, 0x17, 0x8B, 0xE5,
59             0x26, 0x28, 0x23, 0xA1, 0x8A, 0xA4, 0x29, 0xEA, 0xFD, 0x9E,
60             0x39, 0x60, 0x8A, 0xF3, 0xB5, 0xA6, 0xEB, 0x3F, 0x02, 0xB6,
61             0x16, 0xC3, 0x96, 0x9D, 0x38, 0xB0, 0x7D, 0x82, 0x87, 0x0C,
62             0xF7, 0xBE, 0x24, 0xE5, 0x5F, 0x41, 0x04, 0x79, 0x76, 0x40,
63             0xE7, 0x00, 0x22, 0x7E, 0xB5, 0x85, 0x7F, 0x8D, 0x01, 0x50,
64             0xE9, 0xD3, 0x29, 0x42, 0x08, 0xB3, 0x51, 0x40, 0x7B, 0xD7,
65             0x8D, 0xCC, 0x10, 0x01, 0x64, 0x59, 0x28, 0xB6, 0x53, 0xF3,
66             0x50, 0x4E, 0xB1, 0xF2, 0x58, 0xCD, 0x6E, 0xF5, 0x56, 0x3E,
67             0x66, 0x2F, 0xD7, 0x07, 0x7F, 0x52, 0x4C, 0x13, 0x24, 0xDC,
68             0x8E, 0x8D, 0xCC, 0xED, 0x77, 0xC4, 0x21, 0xD2, 0xFD, 0x08,
69             0xEA, 0xD7, 0xC0, 0x5C, 0x13, 0x82, 0x81, 0x31, 0x2F, 0x2B,
70             0x08, 0xE4, 0x80, 0x04, 0x7A, 0x0C, 0x8A, 0x3C, 0xDC, 0x22,
71             0xE4, 0x5A, 0x7A, 0xB0, 0x12, 0x5E, 0x4A, 0x76, 0x94, 0x77,
72             0xC2, 0x0E, 0x92, 0xBA, 0x8A, 0xA0, 0x1F, 0x14, 0x51, 0x1E,
73             0x66, 0x6C, 0x38, 0x03, 0x6C, 0xC7, 0x4A, 0x4B, 0x70, 0x80,
74             0xAF, 0xCA, 0x84, 0x51, 0xD8, 0xD2, 0x26, 0x49, 0xF5, 0xA8,
75             0x5E, 0x35, 0x4B, 0xAC, 0xCE, 0x29, 0x92, 0x33, 0xB7, 0xA2,
76             0x69, 0x7D, 0x0C, 0xE0, 0x9C, 0xDB, 0x04, 0xD6, 0xB4, 0xBC,
77             0x39, 0xD7, 0x7F, 0x9E, 0x9D, 0x78, 0x38, 0x7F, 0x51, 0x54,
78             0x50, 0x8B, 0x9E, 0x9C, 0x03, 0x6C, 0xF5, 0x9D, 0x2C, 0x74,
79             0x57, 0xF0, 0x27, 0x2A, 0xC3, 0x47, 0xCA, 0xB9, 0xD7, 0x5C,
80             0xFF, 0xC2, 0xAC, 0x65, 0x4E, 0xBD
81             };
82              
83             /*
84             * We need temporary values for at least 7 integers of the same size
85             * as a factor (including header word); more space helps with performance
86             * (in modular exponentiations), but we much prefer to remain under
87             * 2 kilobytes in total, to save stack space. The macro TEMPS below
88             * exceeds 1024 (which is a count in 16-bit words) when BR_MAX_RSA_SIZE
89             * is greater than 4350 (default value is 4096, so the 2-kB limit is
90             * maintained unless BR_MAX_RSA_SIZE was modified).
91             */
92             #define MAX(x, y) ((x) > (y) ? (x) : (y))
93             #define TEMPS MAX(1024, 7 * ((((BR_MAX_RSA_SIZE + 1) >> 1) + 29) / 15))
94              
95             /*
96             * Perform trial division on a candidate prime. This computes
97             * y = SMALL_PRIMES mod x, then tries to compute y/y mod x. The
98             * br_i15_moddiv() function will report an error if y is not invertible
99             * modulo x. Returned value is 1 on success (none of the small primes
100             * divides x), 0 on error (a non-trivial GCD is obtained).
101             *
102             * This function assumes that x is odd.
103             */
104             static uint32_t
105 0           trial_divisions(const uint16_t *x, uint16_t *t)
106             {
107             uint16_t *y;
108             uint16_t x0i;
109              
110 0           y = t;
111 0           t += 1 + ((x[0] + 15) >> 4);
112 0           x0i = br_i15_ninv15(x[1]);
113 0           br_i15_decode_reduce(y, SMALL_PRIMES, sizeof SMALL_PRIMES, x);
114 0           return br_i15_moddiv(y, y, x, x0i, t);
115             }
116              
117             /*
118             * Perform n rounds of Miller-Rabin on the candidate prime x. This
119             * function assumes that x = 3 mod 4.
120             *
121             * Returned value is 1 on success (all rounds completed successfully),
122             * 0 otherwise.
123             */
124             static uint32_t
125 0           miller_rabin(const br_prng_class **rng, const uint16_t *x, int n,
126             uint16_t *t, size_t tlen)
127             {
128             /*
129             * Since x = 3 mod 4, the Miller-Rabin test is simple:
130             * - get a random base a (such that 1 < a < x-1)
131             * - compute z = a^((x-1)/2) mod x
132             * - if z != 1 and z != x-1, the number x is composite
133             *
134             * We generate bases 'a' randomly with a size which is
135             * one bit less than x, which ensures that a < x-1. It
136             * is not useful to verify that a > 1 because the probability
137             * that we get a value a equal to 0 or 1 is much smaller
138             * than the probability of our Miller-Rabin tests not to
139             * detect a composite, which is already quite smaller than the
140             * probability of the hardware misbehaving and return a
141             * composite integer because of some glitch (e.g. bad RAM
142             * or ill-timed cosmic ray).
143             */
144             unsigned char *xm1d2;
145             size_t xlen, xm1d2_len, xm1d2_len_u16, u;
146             uint32_t asize;
147             unsigned cc;
148             uint16_t x0i;
149              
150             /*
151             * Compute (x-1)/2 (encoded).
152             */
153 0           xm1d2 = (unsigned char *)t;
154 0           xm1d2_len = ((x[0] - (x[0] >> 4)) + 7) >> 3;
155 0           br_i15_encode(xm1d2, xm1d2_len, x);
156 0           cc = 0;
157 0 0         for (u = 0; u < xm1d2_len; u ++) {
158             unsigned w;
159              
160 0           w = xm1d2[u];
161 0           xm1d2[u] = (unsigned char)((w >> 1) | cc);
162 0           cc = w << 7;
163             }
164              
165             /*
166             * We used some words of the provided buffer for (x-1)/2.
167             */
168 0           xm1d2_len_u16 = (xm1d2_len + 1) >> 1;
169 0           t += xm1d2_len_u16;
170 0           tlen -= xm1d2_len_u16;
171              
172 0           xlen = (x[0] + 15) >> 4;
173 0           asize = x[0] - 1 - EQ0(x[0] & 15);
174 0           x0i = br_i15_ninv15(x[1]);
175 0 0         while (n -- > 0) {
176             uint16_t *a;
177             uint32_t eq1, eqm1;
178              
179             /*
180             * Generate a random base. We don't need the base to be
181             * really uniform modulo x, so we just get a random
182             * number which is one bit shorter than x.
183             */
184 0           a = t;
185 0           a[0] = x[0];
186 0           a[xlen] = 0;
187 0           mkrand(rng, a, asize);
188              
189             /*
190             * Compute a^((x-1)/2) mod x. We assume here that the
191             * function will not fail (the temporary array is large
192             * enough).
193             */
194 0           br_i15_modpow_opt(a, xm1d2, xm1d2_len,
195 0           x, x0i, t + 1 + xlen, tlen - 1 - xlen);
196              
197             /*
198             * We must obtain either 1 or x-1. Note that x is odd,
199             * hence x-1 differs from x only in its low word (no
200             * carry).
201             */
202 0           eq1 = a[1] ^ 1;
203 0           eqm1 = a[1] ^ (x[1] - 1);
204 0 0         for (u = 2; u <= xlen; u ++) {
205 0           eq1 |= a[u];
206 0           eqm1 |= a[u] ^ x[u];
207             }
208              
209 0 0         if ((EQ0(eq1) | EQ0(eqm1)) == 0) {
210 0           return 0;
211             }
212             }
213 0           return 1;
214             }
215              
216             /*
217             * Create a random prime of the provided size. 'size' is the _encoded_
218             * bit length. The two top bits and the two bottom bits are set to 1.
219             */
220             static void
221 0           mkprime(const br_prng_class **rng, uint16_t *x, uint32_t esize,
222             uint32_t pubexp, uint16_t *t, size_t tlen)
223             {
224             size_t len;
225              
226 0           x[0] = esize;
227 0           len = (esize + 15) >> 4;
228 0           for (;;) {
229             size_t u;
230             uint32_t m3, m5, m7, m11;
231             int rounds;
232              
233             /*
234             * Generate random bits. We force the two top bits and the
235             * two bottom bits to 1.
236             */
237 0           mkrand(rng, x, esize);
238 0 0         if ((esize & 15) == 0) {
239 0           x[len] |= 0x6000;
240 0 0         } else if ((esize & 15) == 1) {
241 0           x[len] |= 0x0001;
242 0           x[len - 1] |= 0x4000;
243             } else {
244 0           x[len] |= 0x0003 << ((esize & 15) - 2);
245             }
246 0           x[1] |= 0x0003;
247              
248             /*
249             * Trial division with low primes (3, 5, 7 and 11). We
250             * use the following properties:
251             *
252             * 2^2 = 1 mod 3
253             * 2^4 = 1 mod 5
254             * 2^3 = 1 mod 7
255             * 2^10 = 1 mod 11
256             */
257 0           m3 = 0;
258 0           m5 = 0;
259 0           m7 = 0;
260 0           m11 = 0;
261 0 0         for (u = 0; u < len; u ++) {
262             uint32_t w;
263              
264 0           w = x[1 + u];
265 0           m3 += w << (u & 1);
266 0           m3 = (m3 & 0xFF) + (m3 >> 8);
267 0           m5 += w << ((4 - u) & 3);
268 0           m5 = (m5 & 0xFF) + (m5 >> 8);
269 0           m7 += w;
270 0           m7 = (m7 & 0x1FF) + (m7 >> 9);
271 0           m11 += w << (5 & -(u & 1));
272 0           m11 = (m11 & 0x3FF) + (m11 >> 10);
273             }
274              
275             /*
276             * Maximum values of m* at this point:
277             * m3: 511
278             * m5: 2310
279             * m7: 510
280             * m11: 2047
281             * We use the same properties to make further reductions.
282             */
283              
284 0           m3 = (m3 & 0x0F) + (m3 >> 4); /* max: 46 */
285 0           m3 = (m3 & 0x0F) + (m3 >> 4); /* max: 16 */
286 0           m3 = ((m3 * 43) >> 5) & 3;
287              
288 0           m5 = (m5 & 0xFF) + (m5 >> 8); /* max: 263 */
289 0           m5 = (m5 & 0x0F) + (m5 >> 4); /* max: 30 */
290 0           m5 = (m5 & 0x0F) + (m5 >> 4); /* max: 15 */
291 0           m5 -= 10 & -GT(m5, 9);
292 0           m5 -= 5 & -GT(m5, 4);
293              
294 0           m7 = (m7 & 0x3F) + (m7 >> 6); /* max: 69 */
295 0           m7 = (m7 & 7) + (m7 >> 3); /* max: 14 */
296 0           m7 = ((m7 * 147) >> 7) & 7;
297              
298             /*
299             * 2^5 = 32 = -1 mod 11.
300             */
301 0           m11 = (m11 & 0x1F) + 66 - (m11 >> 5); /* max: 97 */
302 0           m11 -= 88 & -GT(m11, 87);
303 0           m11 -= 44 & -GT(m11, 43);
304 0           m11 -= 22 & -GT(m11, 21);
305 0           m11 -= 11 & -GT(m11, 10);
306              
307             /*
308             * If any of these modulo is 0, then the candidate is
309             * not prime. Also, if pubexp is 3, 5, 7 or 11, and the
310             * corresponding modulus is 1, then the candidate must
311             * be rejected, because we need e to be invertible
312             * modulo p-1. We can use simple comparisons here
313             * because they won't leak information on a candidate
314             * that we keep, only on one that we reject (and is thus
315             * not secret).
316             */
317 0 0         if (m3 == 0 || m5 == 0 || m7 == 0 || m11 == 0) {
    0          
    0          
    0          
318 0           continue;
319             }
320 0 0         if ((pubexp == 3 && m3 == 1)
    0          
321 0 0         || (pubexp == 5 && m5 == 1)
    0          
322 0 0         || (pubexp == 7 && m7 == 1)
    0          
323 0 0         || (pubexp == 11 && m11 == 1))
    0          
324             {
325 0           continue;
326             }
327              
328             /*
329             * More trial divisions.
330             */
331 0 0         if (!trial_divisions(x, t)) {
332 0           continue;
333             }
334              
335             /*
336             * Miller-Rabin algorithm. Since we selected a random
337             * integer, not a maliciously crafted integer, we can use
338             * relatively few rounds to lower the risk of a false
339             * positive (i.e. declaring prime a non-prime) under
340             * 2^(-80). It is not useful to lower the probability much
341             * below that, since that would be substantially below
342             * the probability of the hardware misbehaving. Sufficient
343             * numbers of rounds are extracted from the Handbook of
344             * Applied Cryptography, note 4.49 (page 149).
345             *
346             * Since we work on the encoded size (esize), we need to
347             * compare with encoded thresholds.
348             */
349 0 0         if (esize < 320) {
350 0           rounds = 12;
351 0 0         } else if (esize < 480) {
352 0           rounds = 9;
353 0 0         } else if (esize < 693) {
354 0           rounds = 6;
355 0 0         } else if (esize < 906) {
356 0           rounds = 4;
357 0 0         } else if (esize < 1386) {
358 0           rounds = 3;
359             } else {
360 0           rounds = 2;
361             }
362              
363 0 0         if (miller_rabin(rng, x, rounds, t, tlen)) {
364 0           return;
365             }
366             }
367             }
368              
369             /*
370             * Let p be a prime (p > 2^33, p = 3 mod 4). Let m = (p-1)/2, provided
371             * as parameter (with announced bit length equal to that of p). This
372             * function computes d = 1/e mod p-1 (for an odd integer e). Returned
373             * value is 1 on success, 0 on error (an error is reported if e is not
374             * invertible modulo p-1).
375             *
376             * The temporary buffer (t) must have room for at least 4 integers of
377             * the size of p.
378             */
379             static uint32_t
380 0           invert_pubexp(uint16_t *d, const uint16_t *m, uint32_t e, uint16_t *t)
381             {
382             uint16_t *f;
383             uint32_t r;
384              
385 0           f = t;
386 0           t += 1 + ((m[0] + 15) >> 4);
387              
388             /*
389             * Compute d = 1/e mod m. Since p = 3 mod 4, m is odd.
390             */
391 0           br_i15_zero(d, m[0]);
392 0           d[1] = 1;
393 0           br_i15_zero(f, m[0]);
394 0           f[1] = e & 0x7FFF;
395 0           f[2] = (e >> 15) & 0x7FFF;
396 0           f[3] = e >> 30;
397 0           r = br_i15_moddiv(d, f, m, br_i15_ninv15(m[1]), t);
398              
399             /*
400             * We really want d = 1/e mod p-1, with p = 2m. By the CRT,
401             * the result is either the d we got, or d + m.
402             *
403             * Let's write e*d = 1 + k*m, for some integer k. Integers e
404             * and m are odd. If d is odd, then e*d is odd, which implies
405             * that k must be even; in that case, e*d = 1 + (k/2)*2m, and
406             * thus d is already fine. Conversely, if d is even, then k
407             * is odd, and we must add m to d in order to get the correct
408             * result.
409             */
410 0           br_i15_add(d, m, (uint32_t)(1 - (d[1] & 1)));
411              
412 0           return r;
413             }
414              
415             /*
416             * Swap two buffers in RAM. They must be disjoint.
417             */
418             static void
419 0           bufswap(void *b1, void *b2, size_t len)
420             {
421             size_t u;
422             unsigned char *buf1, *buf2;
423              
424 0           buf1 = b1;
425 0           buf2 = b2;
426 0 0         for (u = 0; u < len; u ++) {
427             unsigned w;
428              
429 0           w = buf1[u];
430 0           buf1[u] = buf2[u];
431 0           buf2[u] = w;
432             }
433 0           }
434              
435             /* see bearssl_rsa.h */
436             uint32_t
437 0           br_rsa_i15_keygen(const br_prng_class **rng,
438             br_rsa_private_key *sk, void *kbuf_priv,
439             br_rsa_public_key *pk, void *kbuf_pub,
440             unsigned size, uint32_t pubexp)
441             {
442             uint32_t esize_p, esize_q;
443             size_t plen, qlen, tlen;
444             uint16_t *p, *q, *t;
445             uint16_t tmp[TEMPS];
446             uint32_t r;
447              
448 0 0         if (size < BR_MIN_RSA_SIZE || size > BR_MAX_RSA_SIZE) {
    0          
449 0           return 0;
450             }
451 0 0         if (pubexp == 0) {
452 0           pubexp = 3;
453 0 0         } else if (pubexp == 1 || (pubexp & 1) == 0) {
    0          
454 0           return 0;
455             }
456              
457 0           esize_p = (size + 1) >> 1;
458 0           esize_q = size - esize_p;
459 0           sk->n_bitlen = size;
460 0           sk->p = kbuf_priv;
461 0           sk->plen = (esize_p + 7) >> 3;
462 0           sk->q = sk->p + sk->plen;
463 0           sk->qlen = (esize_q + 7) >> 3;
464 0           sk->dp = sk->q + sk->qlen;
465 0           sk->dplen = sk->plen;
466 0           sk->dq = sk->dp + sk->dplen;
467 0           sk->dqlen = sk->qlen;
468 0           sk->iq = sk->dq + sk->dqlen;
469 0           sk->iqlen = sk->plen;
470              
471 0 0         if (pk != NULL) {
472 0           pk->n = kbuf_pub;
473 0           pk->nlen = (size + 7) >> 3;
474 0           pk->e = pk->n + pk->nlen;
475 0           pk->elen = 4;
476 0           br_enc32be(pk->e, pubexp);
477 0 0         while (*pk->e == 0) {
478 0           pk->e ++;
479 0           pk->elen --;
480             }
481             }
482              
483             /*
484             * We now switch to encoded sizes.
485             *
486             * floor((x * 17477) / (2^18)) is equal to floor(x/15) for all
487             * integers x from 0 to 23833.
488             */
489 0           esize_p += MUL15(esize_p, 17477) >> 18;
490 0           esize_q += MUL15(esize_q, 17477) >> 18;
491 0           plen = (esize_p + 15) >> 4;
492 0           qlen = (esize_q + 15) >> 4;
493 0           p = tmp;
494 0           q = p + 1 + plen;
495 0           t = q + 1 + qlen;
496 0           tlen = ((sizeof tmp) / sizeof(uint16_t)) - (2 + plen + qlen);
497              
498             /*
499             * When looking for primes p and q, we temporarily divide
500             * candidates by 2, in order to compute the inverse of the
501             * public exponent.
502             */
503              
504             for (;;) {
505 0           mkprime(rng, p, esize_p, pubexp, t, tlen);
506 0           br_i15_rshift(p, 1);
507 0 0         if (invert_pubexp(t, p, pubexp, t + 1 + plen)) {
508 0           br_i15_add(p, p, 1);
509 0           p[1] |= 1;
510 0           br_i15_encode(sk->p, sk->plen, p);
511 0           br_i15_encode(sk->dp, sk->dplen, t);
512 0           break;
513             }
514             }
515              
516             for (;;) {
517 0           mkprime(rng, q, esize_q, pubexp, t, tlen);
518 0           br_i15_rshift(q, 1);
519 0 0         if (invert_pubexp(t, q, pubexp, t + 1 + qlen)) {
520 0           br_i15_add(q, q, 1);
521 0           q[1] |= 1;
522 0           br_i15_encode(sk->q, sk->qlen, q);
523 0           br_i15_encode(sk->dq, sk->dqlen, t);
524 0           break;
525             }
526             }
527              
528             /*
529             * If p and q have the same size, then it is possible that q > p
530             * (when the target modulus size is odd, we generate p with a
531             * greater bit length than q). If q > p, we want to swap p and q
532             * (and also dp and dq) for two reasons:
533             * - The final step below (inversion of q modulo p) is easier if
534             * p > q.
535             * - While BearSSL's RSA code is perfectly happy with RSA keys such
536             * that p < q, some other implementations have restrictions and
537             * require p > q.
538             *
539             * Note that we can do a simple non-constant-time swap here,
540             * because the only information we leak here is that we insist on
541             * returning p and q such that p > q, which is not a secret.
542             */
543 0 0         if (esize_p == esize_q && br_i15_sub(p, q, 0) == 1) {
    0          
544 0           bufswap(p, q, (1 + plen) * sizeof *p);
545 0           bufswap(sk->p, sk->q, sk->plen);
546 0           bufswap(sk->dp, sk->dq, sk->dplen);
547             }
548              
549             /*
550             * We have produced p, q, dp and dq. We can now compute iq = 1/d mod p.
551             *
552             * We ensured that p >= q, so this is just a matter of updating the
553             * header word for q (and possibly adding an extra word).
554             *
555             * Theoretically, the call below may fail, in case we were
556             * extraordinarily unlucky, and p = q. Another failure case is if
557             * Miller-Rabin failed us _twice_, and p and q are non-prime and
558             * have a factor is common. We report the error mostly because it
559             * is cheap and we can, but in practice this never happens (or, at
560             * least, it happens way less often than hardware glitches).
561             */
562 0           q[0] = p[0];
563 0 0         if (plen > qlen) {
564 0           q[plen] = 0;
565 0           t ++;
566 0           tlen --;
567             }
568 0           br_i15_zero(t, p[0]);
569 0           t[1] = 1;
570 0           r = br_i15_moddiv(t, q, p, br_i15_ninv15(p[1]), t + 1 + plen);
571 0           br_i15_encode(sk->iq, sk->iqlen, t);
572              
573             /*
574             * Compute the public modulus too, if required.
575             */
576 0 0         if (pk != NULL) {
577 0           br_i15_zero(t, p[0]);
578 0           br_i15_mulacc(t, p, q);
579 0           br_i15_encode(pk->n, pk->nlen, t);
580             }
581              
582 0           return r;
583             }