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package Math::Round::Fair; |
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123381
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use warnings; |
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use strict; |
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use 5.005000; |
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use Devel::Assert; |
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69948
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use Carp; |
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use base qw/Exporter/; |
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use List::Util qw/shuffle sum min/; |
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use POSIX qw/floor ceil DBL_EPSILON/; |
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49074
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our $VERSION = '0.03'; |
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our @EXPORT_OK = qw/round_fair round_adjacent/; |
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BEGIN { |
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my $debug; |
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902
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sub DEBUG { $debug } |
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$debug = $ENV{MATH_ROUND_FAIR_DEBUG} || 0; |
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use Devel::Assert DEBUG() ? ('-all -verbose') : (); |
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# used in assertions |
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eval q{use Perl6::Junction 'none'} if DEBUG(); |
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} |
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=head1 NAME |
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Math::Round::Fair - distribute rounding errors fairly |
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31
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=head1 SYNOPSIS |
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33
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use Math::Round::Fair 'round_fair', 'round_adjacent'; |
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35
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my $cents = 7; |
36
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my @weights = (1, 2, 3, 2, 1); |
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my @allocation = round_fair($cents, @weights); |
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39
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print "@allocation\n"; |
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41
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# output will be one of the following: |
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# 0 1 3 2 1 |
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# 0 2 2 2 1 |
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# 0 2 3 1 1 |
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# 0 2 3 2 0 |
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# 1 1 2 2 1 |
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# 1 1 3 1 1 |
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# 1 1 3 2 0 |
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# 1 2 2 1 1 |
50
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# 1 2 2 2 0 |
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52
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my @total; |
53
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for ( 1..900 ) { |
54
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@allocation = round_fair($cents, @weights); |
55
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@total[$_] += @allocation[$_] for 0..$#allocation; |
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} |
57
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print "@total\n"; |
58
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59
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# output will be *near* 700 1400 2100 1400 700, e.g.: |
60
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# 698 1411 2096 1418 677 |
61
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62
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63
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my @rounded = round_adjacent(0.95, 0.65, 0.41, 0.99); |
64
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# @rounded will be one of the following: |
65
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# 59% of the time: 1, 1, 0, 1 |
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# 35% of the time: 1, 0, 1, 1 |
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# 5% of the time: 0, 1, 1, 1 |
68
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# 1% of the time: 1, 1, 1, 0 |
69
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70
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71
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=head1 DESCRIPTION |
72
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73
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This module provides two exportable functions, C, which |
74
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allocates an integer value, fairly distributing rounding errors, and |
75
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C, which takes a list of real numbers and rounds them up, or |
76
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down, to an adjacent integer, fairly. Both functions return a list of fairly |
77
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rounded integer values. |
78
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79
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C and C round up, or down, randomly, where the |
80
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probability of rounding up is equal to the fraction to round. For example, 0.5 |
81
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will round to 1.0 with a probability of 0.5. 0.3 will round to 1.0 3 out of 10 |
82
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times and to zero 7 out of 10 times, on average. |
83
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84
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Consider the problem of distributing one indivisible item, for example a penny, |
85
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across three evenly weighted accounts, A, B, and C. |
86
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87
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Using a naive approach, none of the accounts will receive an allocation since |
88
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the allocated portion to each is 1/3 and 1/3 rounds to zero. We are left with |
89
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1 unallocated item. |
90
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91
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Another approach is to adjust the basis at each step. We start with 1 item to |
92
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allocate to 3 accounts. 1/3 rounds to 0, so account A receives no allocation, |
93
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and we drop it from consideration. Now, we have 2 accounts and one item to |
94
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allocate. 1/2 rounds to 1, so we allocate 1 item to account B. Account C |
95
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gets no allocation since there is nothing left to allocate. |
96
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97
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But what happens if we allocate one item to the same three accounts 10,000 |
98
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times? Ideally, two accounts should end up with 3,333 items and one should end |
99
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up with 3,334 items. |
100
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101
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Using the naive approach, all three accounts receive no allocation since at |
102
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each round the allocation is 1/3 which rounds to zero. Using the second method, |
103
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account A and account C will receive no allocation, and account B will receive |
104
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a total allocation of 10,000 items. Account B always receives the benefit of |
105
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the rounding errors using the second method. |
106
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107
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The algorithm employed by this module uses randomness to ensure a fair distribution of |
108
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rounding errors. In our example problem, we start with 1 item to allocate. We |
109
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calculate account A's share, 1/3. Since it is less than one item, we give it a |
110
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1/3 chance of rounding up (and, therefore, a 2/3 chance of rounding down). It |
111
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wins the allocation 1/3 of the time. 2/3 of the time we continue to B. We |
112
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calculate B's allocation as 1/2 (since there are only 2 accounts remaining and |
113
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one item to allocate). B rounds up 1/2 of 2/3 (or 1/3) of the time and down |
114
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1/2 of 2/3 (or 1/3) of the time. If neither A nor B rounds up (which occurs |
115
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2/3 * 1/2, or 1/3 of the time), C's allocation is calculated as 1/1 since we |
116
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have one item to allocate and only one account to allocate it to. So, 1/3 of |
117
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the time C receives the benefit of the rounding error. We never end up with |
118
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any unallocated items. |
119
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120
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This algorithm works for any number of weighted allocations. |
121
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122
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=over 4 |
123
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124
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=item round_fair($value, @weights) |
125
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126
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Returns a list of integer values that sum to C<$value> where each return value |
127
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is a portion of C<$value> allocated by the respective weights in C<@weights>. |
128
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The number of return values is equal to the number of elements in C<@weights> |
129
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130
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C<$value> must be an integer. |
131
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132
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=cut |
133
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134
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sub round_fair { |
135
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52
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52
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1
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268
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my $value = shift; |
136
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137
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52
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50
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33
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221
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croak "Value to be allocated must be an integer >= 0" unless int($value) == $value && $value >= 0; |
138
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139
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52
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50
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106
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return ($value) if @_ == 1; |
140
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52
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50
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92
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return (0) x @_ if $value == 0; |
141
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142
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52
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50
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my $basis = 0; |
143
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52
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76
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for my $w ( @_ ) { |
144
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214
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50
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306
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croak "Weights must be > 0" unless $w > 0; |
145
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214
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307
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$basis += $w; |
146
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} |
147
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148
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52
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68
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my $sum = 0; |
149
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52
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79
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my @in = map { my $r = $value * $_ / $basis; $sum += $r; $r } @_; |
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214
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268
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214
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202
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214
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322
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150
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151
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# First, create the extra entry for the total, so that the sum of |
152
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# the new array is zero. |
153
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52
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75
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push @in, -$sum; |
154
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155
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52
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104
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my $out = _round_adjacent_arrayref(\@in); |
156
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52
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66
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pop @$out; # Discard the entry for the total |
157
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158
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52
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160
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return @$out; |
159
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} |
160
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161
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=item round_adjacent(@input_values) |
162
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163
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Returns a list of integer values, each of which is numerically |
164
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adjacent to the corresponding element of @input_values, and whose total is |
165
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numerically adjacent to the total of @input_values. |
166
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167
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The expected value of each output value is equal to the corresponding element |
168
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of @input_values (within a small error margin due to the limited machine |
169
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precision). |
170
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171
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=cut |
172
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173
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sub round_adjacent { |
174
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11002
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100
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11002
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1
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549496
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return () unless @_; # identity |
175
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176
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# First, create the extra entry for the total, so that the sum of |
177
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# the new array is zero. |
178
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11001
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29270
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push @_, -sum(@_); |
179
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180
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# use a reference to eliminate an unnecessary copy |
181
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11001
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20226
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my $out = _round_adjacent_arrayref(\@_); |
182
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183
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11001
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13537
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pop @$out; # Discard the entry for the total |
184
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11001
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43021
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return @$out; |
185
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} |
186
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187
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sub _round_adjacent_arrayref { |
188
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11053
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11053
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12493
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my $in = shift; |
189
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190
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# Next, shuffle the order, so that the input order has no effect |
191
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# on the randomness characteristics. |
192
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6
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6
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5433
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my @order = shuffle($[ .. $#{$in}); |
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6
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2884
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6
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493
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11053
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11878
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11053
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47166
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193
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11053
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59562
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@$in = map $in->[$_], @order; |
194
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195
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11053
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22868
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my $out = _round_adjacent_core($in); |
196
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197
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11053
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10678
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assert(sum(@$out) == 0); |
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# put the output back into original order |
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my @r; |
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84125
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$r[$order[$_]] = $out->[$_] for $[ .. $#order; |
202
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35240
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return \@r; |
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} |
205
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# Like _round_adjacent_arrayref, except that the inputs must sum to zero, and the |
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# input order may affect the variance and correlations, etc. |
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sub _round_adjacent_core { |
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11717
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my $in = shift; |
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9501
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assert(scalar @$in); # @$in must not be empty |
212
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213
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11053
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15382
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my $eps1 = 4.0 * DBL_EPSILON() * (1 + @$in); |
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11139
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my $eps = $eps1; |
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13297
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my @fp = map { my $ip = floor($_); $_ - $ip } @$in; |
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70270
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95160
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70270
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118278
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216
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11053
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12915
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assert(none(@fp) < 0.0); |
218
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219
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# TBD: Maybe accuracy or fairness can be improved by |
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# re-adjusting after every iteration. This would slow it |
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# down significantly, though. |
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17885
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_adjust_input(\@fp); |
223
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224
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11053
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13313
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my @out; |
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11053
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10873
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INPUT: while() { |
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11053
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10188
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226
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70270
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77023
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$eps += $eps1; |
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11053
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22648
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227
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228
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70270
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63601
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assert(_check_invariants($eps, $in, \@fp)); |
229
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230
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11053
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11053
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12400
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# Calculate the next output. Discard the next input in the |
231
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# process. |
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70270
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79956
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my $p0 = shift @fp; # Probability of having to overpay |
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70270
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100
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132633
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my $r0 = rand()<$p0 ? 1 : 0; # 1 if selected to overpay; else 0 |
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70270
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169667
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push @out, floor(shift @$in) + $r0; |
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11053
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19906
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235
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11053
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100
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37553
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236
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70270
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100
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130914
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last unless @fp; |
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7229
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238
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4016
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50
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18880
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# Now adjust the remaining fractional parts. |
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240
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# $slack[i] = min( $p0 * $fp[i], (1-$p0) * (1-$fp[i]) ). |
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59217
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61327
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my @slack; |
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4016
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4411
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242
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59217
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100
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57856
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my $tslack = 0.0; |
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4016
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6827
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243
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59217
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60727
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do { |
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2616
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14147
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244
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@slack = map { |
245
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59217
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67364
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if ( 1 ) { |
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502371
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445559
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1400
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2080
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246
|
502371
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927402
|
my $slack = min $p0 * $_, (1 - $_) * (1.0 - $p0); |
|
1400
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13129
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247
|
502371
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520563
|
$tslack += $slack; |
248
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502371
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726121
|
$slack; |
249
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} |
250
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else { |
251
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# This is fewer FLOPS, but the perf benefit |
252
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0
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0
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|
|
# is only 1% on a modern system, and it leads |
253
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|
# to greater numerical errors for some reason. |
254
|
0
|
0
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|
|
my $add = $p0 + $_; |
|
0
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255
|
0
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|
|
my $mult = $p0 * $_; |
256
|
0
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|
|
$add > 1.0 ? 1.0 - $add + $mult : $mult |
257
|
0
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|
|
} |
258
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0
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|
|
} @fp; |
259
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|
|
}; |
260
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|
261
|
0
|
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|
|
# See bottom of file for proof of this property: |
262
|
59217
|
|
|
|
|
69392
|
assert($tslack + $eps >= $p0 * (1.0 - $p0)); |
|
0
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|
263
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264
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0
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|
|
# wrapped in assert to make it a noop when DEBUG() == 0 |
265
|
59217
|
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|
51205
|
assert(do { warn "TSLACK = $tslack\n" if DEBUG() > 1; 1 }); |
266
|
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|
267
|
59217
|
100
|
|
|
|
117893
|
if ( $tslack > $eps1 ) { |
268
|
37168
|
|
|
|
|
51714
|
$eps += 128.0 * $eps1 * $eps / $tslack; |
269
|
|
|
|
|
|
|
# NOTE: The expected value of gain is |
270
|
|
|
|
|
|
|
# $p0 * ($p0 - 1.0) /$tslack + |
271
|
|
|
|
|
|
|
# (1.0 - $p0) * $p0 / $tslack = 0 |
272
|
37168
|
|
|
|
|
33430
|
my $gain = do { |
273
|
37168
|
100
|
|
|
|
57291
|
if ( $r0 ) { |
274
|
|
|
|
|
|
|
# Last guy overpaid, so the probabilities for |
275
|
|
|
|
|
|
|
# subsequent payers drop. |
276
|
17549
|
|
|
|
|
23108
|
($p0 - 1.0) / $tslack; |
277
|
|
|
|
|
|
|
} |
278
|
|
|
|
|
|
|
else { |
279
|
|
|
|
|
|
|
# Last guy underpaid, so the probabilities for |
280
|
|
|
|
|
|
|
# subsequent payers rise. |
281
|
19619
|
|
|
|
|
23664
|
$p0 / $tslack; |
282
|
|
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|
|
} |
283
|
|
|
|
|
|
|
}; |
284
|
|
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|
|
285
|
|
|
|
|
|
|
# NOTE: The change in the sum of @fp due to this step |
286
|
|
|
|
|
|
|
# is $tslack * $gain, which is either $p0 or ($p0 - 1). |
287
|
|
|
|
|
|
|
# Either way, the sum remains an integer, because it |
288
|
|
|
|
|
|
|
# was reduced by $p0 when we shifted off the first |
289
|
|
|
|
|
|
|
# element early in the INPUT loop iteration. |
290
|
|
|
|
|
|
|
# Also note that each element of @fp stays in the range |
291
|
|
|
|
|
|
|
# [0,1] because if $r0, then slack($_, $p0) * -$gain <= |
292
|
|
|
|
|
|
|
# $p0 * $_ * (1.0 - $p0) / ($p0 * (1.0 - $p0)) == |
293
|
|
|
|
|
|
|
# $_, and otherwise slack($_, $p0) * $gain <= |
294
|
|
|
|
|
|
|
# (1 - $p0) * (1 - $_) * $p0 / ($p0 * (1.0 - $p0)) == |
295
|
|
|
|
|
|
|
# 1 - $_. |
296
|
|
|
|
|
|
|
# We modify in place here, for performance. |
297
|
37168
|
|
|
|
|
225908
|
$_ += shift(@slack) * $gain for @fp; |
298
|
|
|
|
|
|
|
} |
299
|
|
|
|
|
|
|
} |
300
|
|
|
|
|
|
|
assert(@$in == 0); |
301
|
|
|
|
|
|
|
return \@out; |
302
|
|
|
|
|
|
|
} |
303
|
|
|
|
|
|
|
|
304
|
|
|
|
|
|
|
sub _adjust_input { |
305
|
|
|
|
|
|
|
my $p = shift; |
306
|
|
|
|
|
|
|
|
307
|
|
|
|
|
|
|
# Adjust @$p to account for numerical errors due to small |
308
|
|
|
|
|
|
|
# difference of large numbers when the integer parts are big. |
309
|
|
|
|
|
|
|
my $sum = sum @$p; |
310
|
|
|
|
|
|
|
if ( $sum != floor($sum) ) { |
311
|
|
|
|
|
|
|
my $target = floor($sum + 0.5); |
312
|
|
|
|
|
|
|
|
313
|
|
|
|
|
|
|
die "Total loss of precision" |
314
|
|
|
|
|
|
|
unless abs($sum - $target) < 0.1 && $sum + 0.05 != $sum; |
315
|
|
|
|
|
|
|
|
316
|
|
|
|
|
|
|
my $adj = $target / $sum; |
317
|
|
|
|
|
|
|
if ( $adj <= 1.0 ) { |
318
|
|
|
|
|
|
|
$_ *= $adj for @$p; |
319
|
|
|
|
|
|
|
} else { |
320
|
|
|
|
|
|
|
$adj = (@$p - $target) / (@$p - $sum); |
321
|
|
|
|
|
|
|
$_ = 1.0 - (1.0-$_) * $adj for @$p; |
322
|
|
|
|
|
|
|
} |
323
|
|
|
|
|
|
|
} |
324
|
|
|
|
|
|
|
} |
325
|
|
|
|
|
|
|
|
326
|
|
|
|
|
|
|
sub _check_invariants { |
327
|
|
|
|
|
|
|
my ( $eps, $v, $fp ) = @_; |
328
|
|
|
|
|
|
|
|
329
|
|
|
|
|
|
|
if ( DEBUG() > 1 ) { |
330
|
|
|
|
|
|
|
warn sprintf "%d %f\n", floor($_), $_ for @$fp; |
331
|
|
|
|
|
|
|
} |
332
|
|
|
|
|
|
|
|
333
|
|
|
|
|
|
|
assert(@$v && @$v == @$fp); |
334
|
|
|
|
|
|
|
|
335
|
|
|
|
|
|
|
for ( @$fp ) { |
336
|
|
|
|
|
|
|
assert($_ >= -$eps); |
337
|
|
|
|
|
|
|
assert($_ <= 1.0 + $eps); |
338
|
|
|
|
|
|
|
} |
339
|
|
|
|
|
|
|
|
340
|
|
|
|
|
|
|
my $sum = sum @$fp; |
341
|
|
|
|
|
|
|
assert(abs($sum - floor($sum + 0.5)) < $eps * (1 + $sum)); |
342
|
|
|
|
|
|
|
|
343
|
|
|
|
|
|
|
1; |
344
|
|
|
|
|
|
|
} |
345
|
|
|
|
|
|
|
|
346
|
|
|
|
|
|
|
1; |
347
|
|
|
|
|
|
|
|
348
|
|
|
|
|
|
|
__END__ |