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/* |
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* LibXDiff by Davide Libenzi ( File Differential Library ) |
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* Copyright (C) 2003-2016 Davide Libenzi, Johannes E. Schindelin |
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* |
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* This library is free software; you can redistribute it and/or |
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* modify it under the terms of the GNU Lesser General Public |
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* License as published by the Free Software Foundation; either |
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* version 2.1 of the License, or (at your option) any later version. |
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* |
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* This library is distributed in the hope that it will be useful, |
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* but WITHOUT ANY WARRANTY; without even the implied warranty of |
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU |
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* Lesser General Public License for more details. |
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* |
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* You should have received a copy of the GNU Lesser General Public |
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* License along with this library; if not, see |
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* . |
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* |
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* Davide Libenzi |
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* |
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*/ |
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#include "xinclude.h" |
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/* |
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* The basic idea of patience diff is to find lines that are unique in |
26
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* both files. These are intuitively the ones that we want to see as |
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* common lines. |
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* |
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* The maximal ordered sequence of such line pairs (where ordered means |
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* that the order in the sequence agrees with the order of the lines in |
31
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* both files) naturally defines an initial set of common lines. |
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* |
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* Now, the algorithm tries to extend the set of common lines by growing |
34
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* the line ranges where the files have identical lines. |
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* |
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* Between those common lines, the patience diff algorithm is applied |
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* recursively, until no unique line pairs can be found; these line ranges |
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* are handled by the well-known Myers algorithm. |
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*/ |
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41
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#define NON_UNIQUE ULONG_MAX |
42
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43
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/* |
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* This is a hash mapping from line hash to line numbers in the first and |
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* second file. |
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*/ |
47
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struct hashmap { |
48
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int nr, alloc; |
49
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struct entry { |
50
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unsigned long hash; |
51
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/* |
52
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* 0 = unused entry, 1 = first line, 2 = second, etc. |
53
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* line2 is NON_UNIQUE if the line is not unique |
54
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* in either the first or the second file. |
55
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*/ |
56
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unsigned long line1, line2; |
57
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/* |
58
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* "next" & "previous" are used for the longest common |
59
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* sequence; |
60
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* initially, "next" reflects only the order in file1. |
61
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*/ |
62
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struct entry *next, *previous; |
63
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64
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/* |
65
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* If 1, this entry can serve as an anchor. See |
66
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* Documentation/diff-options.txt for more information. |
67
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*/ |
68
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unsigned anchor : 1; |
69
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} *entries, *first, *last; |
70
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/* were common records found? */ |
71
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unsigned long has_matches; |
72
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mmfile_t *file1, *file2; |
73
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xdfenv_t *env; |
74
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xpparam_t const *xpp; |
75
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}; |
76
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77
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0
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static int is_anchor(xpparam_t const *xpp, const char *line) |
78
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{ |
79
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int i; |
80
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0
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0
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for (i = 0; i < xpp->anchors_nr; i++) { |
81
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0
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0
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if (!strncmp(line, xpp->anchors[i], strlen(xpp->anchors[i]))) |
82
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0
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return 1; |
83
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} |
84
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0
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return 0; |
85
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} |
86
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87
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/* The argument "pass" is 1 for the first file, 2 for the second. */ |
88
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0
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static void insert_record(xpparam_t const *xpp, int line, struct hashmap *map, |
89
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int pass) |
90
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{ |
91
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0
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xrecord_t **records = pass == 1 ? |
92
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0
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0
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map->env->xdf1.recs : map->env->xdf2.recs; |
93
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0
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xrecord_t *record = records[line - 1]; |
94
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/* |
95
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* After xdl_prepare_env() (or more precisely, due to |
96
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* xdl_classify_record()), the "ha" member of the records (AKA lines) |
97
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* is _not_ the hash anymore, but a linearized version of it. In |
98
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* other words, the "ha" member is guaranteed to start with 0 and |
99
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* the second record's ha can only be 0 or 1, etc. |
100
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* |
101
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* So we multiply ha by 2 in the hope that the hashing was |
102
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* "unique enough". |
103
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*/ |
104
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0
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int index = (int)((record->ha << 1) % map->alloc); |
105
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106
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0
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0
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while (map->entries[index].line1) { |
107
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0
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0
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if (map->entries[index].hash != record->ha) { |
108
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0
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0
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if (++index >= map->alloc) |
109
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0
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index = 0; |
110
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0
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continue; |
111
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} |
112
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0
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0
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if (pass == 2) |
113
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0
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map->has_matches = 1; |
114
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0
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0
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if (pass == 1 || map->entries[index].line2) |
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0
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115
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0
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map->entries[index].line2 = NON_UNIQUE; |
116
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else |
117
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0
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map->entries[index].line2 = line; |
118
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0
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return; |
119
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} |
120
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0
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0
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if (pass == 2) |
121
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0
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return; |
122
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0
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map->entries[index].line1 = line; |
123
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0
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map->entries[index].hash = record->ha; |
124
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0
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map->entries[index].anchor = is_anchor(xpp, map->env->xdf1.recs[line - 1]->ptr); |
125
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0
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0
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if (!map->first) |
126
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0
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map->first = map->entries + index; |
127
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0
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0
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if (map->last) { |
128
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0
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map->last->next = map->entries + index; |
129
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0
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map->entries[index].previous = map->last; |
130
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} |
131
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0
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map->last = map->entries + index; |
132
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0
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map->nr++; |
133
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} |
134
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135
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/* |
136
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* This function has to be called for each recursion into the inter-hunk |
137
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* parts, as previously non-unique lines can become unique when being |
138
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* restricted to a smaller part of the files. |
139
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* |
140
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* It is assumed that env has been prepared using xdl_prepare(). |
141
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*/ |
142
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0
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static int fill_hashmap(mmfile_t *file1, mmfile_t *file2, |
143
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xpparam_t const *xpp, xdfenv_t *env, |
144
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struct hashmap *result, |
145
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int line1, int count1, int line2, int count2) |
146
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{ |
147
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0
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result->file1 = file1; |
148
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0
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result->file2 = file2; |
149
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0
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result->xpp = xpp; |
150
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0
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result->env = env; |
151
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152
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/* We know exactly how large we want the hash map */ |
153
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0
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result->alloc = count1 * 2; |
154
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0
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result->entries = (struct entry *) |
155
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0
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xdl_malloc(result->alloc * sizeof(struct entry)); |
156
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0
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0
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if (!result->entries) |
157
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0
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return -1; |
158
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0
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memset(result->entries, 0, result->alloc * sizeof(struct entry)); |
159
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160
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/* First, fill with entries from the first file */ |
161
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0
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0
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while (count1--) |
162
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0
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insert_record(xpp, line1++, result, 1); |
163
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164
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/* Then search for matches in the second file */ |
165
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0
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0
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while (count2--) |
166
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0
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insert_record(xpp, line2++, result, 2); |
167
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168
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0
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return 0; |
169
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} |
170
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171
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/* |
172
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* Find the longest sequence with a smaller last element (meaning a smaller |
173
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* line2, as we construct the sequence with entries ordered by line1). |
174
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*/ |
175
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0
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static int binary_search(struct entry **sequence, int longest, |
176
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struct entry *entry) |
177
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{ |
178
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0
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int left = -1, right = longest; |
179
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180
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0
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0
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while (left + 1 < right) { |
181
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0
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int middle = left + (right - left) / 2; |
182
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/* by construction, no two entries can be equal */ |
183
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0
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0
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if (sequence[middle]->line2 > entry->line2) |
184
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0
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right = middle; |
185
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else |
186
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0
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left = middle; |
187
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} |
188
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/* return the index in "sequence", _not_ the sequence length */ |
189
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0
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return left; |
190
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} |
191
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192
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/* |
193
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* The idea is to start with the list of common unique lines sorted by |
194
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* the order in file1. For each of these pairs, the longest (partial) |
195
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* sequence whose last element's line2 is smaller is determined. |
196
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|
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* |
197
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|
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* For efficiency, the sequences are kept in a list containing exactly one |
198
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|
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* item per sequence length: the sequence with the smallest last |
199
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|
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* element (in terms of line2). |
200
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|
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*/ |
201
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0
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static struct entry *find_longest_common_sequence(struct hashmap *map) |
202
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|
|
|
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{ |
203
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0
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|
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struct entry **sequence = xdl_malloc(map->nr * sizeof(struct entry *)); |
204
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0
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|
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int longest = 0, i; |
205
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|
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|
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struct entry *entry; |
206
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|
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207
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/* |
208
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|
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* If not -1, this entry in sequence must never be overridden. |
209
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|
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* Therefore, overriding entries before this has no effect, so |
210
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|
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|
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* do not do that either. |
211
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|
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*/ |
212
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0
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|
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int anchor_i = -1; |
213
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|
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|
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214
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0
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0
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for (entry = map->first; entry; entry = entry->next) { |
215
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0
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0
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if (!entry->line2 || entry->line2 == NON_UNIQUE) |
|
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0
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216
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0
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continue; |
217
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0
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|
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i = binary_search(sequence, longest, entry); |
218
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0
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0
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|
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entry->previous = i < 0 ? NULL : sequence[i]; |
219
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0
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|
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++i; |
220
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0
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0
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|
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if (i <= anchor_i) |
221
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0
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continue; |
222
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0
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|
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|
sequence[i] = entry; |
223
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0
|
0
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|
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if (entry->anchor) { |
224
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0
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|
|
|
|
|
anchor_i = i; |
225
|
0
|
|
|
|
|
|
longest = anchor_i + 1; |
226
|
0
|
0
|
|
|
|
|
} else if (i == longest) { |
227
|
0
|
|
|
|
|
|
longest++; |
228
|
|
|
|
|
|
|
} |
229
|
|
|
|
|
|
|
} |
230
|
|
|
|
|
|
|
|
231
|
|
|
|
|
|
|
/* No common unique lines were found */ |
232
|
0
|
0
|
|
|
|
|
if (!longest) { |
233
|
0
|
|
|
|
|
|
xdl_free(sequence); |
234
|
0
|
|
|
|
|
|
return NULL; |
235
|
|
|
|
|
|
|
} |
236
|
|
|
|
|
|
|
|
237
|
|
|
|
|
|
|
/* Iterate starting at the last element, adjusting the "next" members */ |
238
|
0
|
|
|
|
|
|
entry = sequence[longest - 1]; |
239
|
0
|
|
|
|
|
|
entry->next = NULL; |
240
|
0
|
0
|
|
|
|
|
while (entry->previous) { |
241
|
0
|
|
|
|
|
|
entry->previous->next = entry; |
242
|
0
|
|
|
|
|
|
entry = entry->previous; |
243
|
|
|
|
|
|
|
} |
244
|
0
|
|
|
|
|
|
xdl_free(sequence); |
245
|
0
|
|
|
|
|
|
return entry; |
246
|
|
|
|
|
|
|
} |
247
|
|
|
|
|
|
|
|
248
|
0
|
|
|
|
|
|
static int match(struct hashmap *map, int line1, int line2) |
249
|
|
|
|
|
|
|
{ |
250
|
0
|
|
|
|
|
|
xrecord_t *record1 = map->env->xdf1.recs[line1 - 1]; |
251
|
0
|
|
|
|
|
|
xrecord_t *record2 = map->env->xdf2.recs[line2 - 1]; |
252
|
0
|
|
|
|
|
|
return record1->ha == record2->ha; |
253
|
|
|
|
|
|
|
} |
254
|
|
|
|
|
|
|
|
255
|
|
|
|
|
|
|
static int patience_diff(mmfile_t *file1, mmfile_t *file2, |
256
|
|
|
|
|
|
|
xpparam_t const *xpp, xdfenv_t *env, |
257
|
|
|
|
|
|
|
int line1, int count1, int line2, int count2); |
258
|
|
|
|
|
|
|
|
259
|
0
|
|
|
|
|
|
static int walk_common_sequence(struct hashmap *map, struct entry *first, |
260
|
|
|
|
|
|
|
int line1, int count1, int line2, int count2) |
261
|
|
|
|
|
|
|
{ |
262
|
0
|
|
|
|
|
|
int end1 = line1 + count1, end2 = line2 + count2; |
263
|
|
|
|
|
|
|
int next1, next2; |
264
|
|
|
|
|
|
|
|
265
|
|
|
|
|
|
|
for (;;) { |
266
|
|
|
|
|
|
|
/* Try to grow the line ranges of common lines */ |
267
|
0
|
0
|
|
|
|
|
if (first) { |
268
|
0
|
|
|
|
|
|
next1 = first->line1; |
269
|
0
|
|
|
|
|
|
next2 = first->line2; |
270
|
0
|
0
|
|
|
|
|
while (next1 > line1 && next2 > line2 && |
271
|
0
|
|
|
|
|
|
match(map, next1 - 1, next2 - 1)) { |
272
|
0
|
|
|
|
|
|
next1--; |
273
|
0
|
|
|
|
|
|
next2--; |
274
|
|
|
|
|
|
|
} |
275
|
|
|
|
|
|
|
} else { |
276
|
0
|
|
|
|
|
|
next1 = end1; |
277
|
0
|
|
|
|
|
|
next2 = end2; |
278
|
|
|
|
|
|
|
} |
279
|
0
|
0
|
|
|
|
|
while (line1 < next1 && line2 < next2 && |
280
|
0
|
|
|
|
|
|
match(map, line1, line2)) { |
281
|
0
|
|
|
|
|
|
line1++; |
282
|
0
|
|
|
|
|
|
line2++; |
283
|
|
|
|
|
|
|
} |
284
|
|
|
|
|
|
|
|
285
|
|
|
|
|
|
|
/* Recurse */ |
286
|
0
|
0
|
|
|
|
|
if (next1 > line1 || next2 > line2) { |
|
|
0
|
|
|
|
|
|
287
|
0
|
0
|
|
|
|
|
if (patience_diff(map->file1, map->file2, |
288
|
|
|
|
|
|
|
map->xpp, map->env, |
289
|
|
|
|
|
|
|
line1, next1 - line1, |
290
|
|
|
|
|
|
|
line2, next2 - line2)) |
291
|
0
|
|
|
|
|
|
return -1; |
292
|
|
|
|
|
|
|
} |
293
|
|
|
|
|
|
|
|
294
|
0
|
0
|
|
|
|
|
if (!first) |
295
|
0
|
|
|
|
|
|
return 0; |
296
|
|
|
|
|
|
|
|
297
|
0
|
0
|
|
|
|
|
while (first->next && |
|
|
0
|
|
|
|
|
|
298
|
0
|
0
|
|
|
|
|
first->next->line1 == first->line1 + 1 && |
299
|
0
|
|
|
|
|
|
first->next->line2 == first->line2 + 1) |
300
|
0
|
|
|
|
|
|
first = first->next; |
301
|
|
|
|
|
|
|
|
302
|
0
|
|
|
|
|
|
line1 = first->line1 + 1; |
303
|
0
|
|
|
|
|
|
line2 = first->line2 + 1; |
304
|
|
|
|
|
|
|
|
305
|
0
|
|
|
|
|
|
first = first->next; |
306
|
0
|
|
|
|
|
|
} |
307
|
|
|
|
|
|
|
} |
308
|
|
|
|
|
|
|
|
309
|
0
|
|
|
|
|
|
static int fall_back_to_classic_diff(struct hashmap *map, |
310
|
|
|
|
|
|
|
int line1, int count1, int line2, int count2) |
311
|
|
|
|
|
|
|
{ |
312
|
|
|
|
|
|
|
xpparam_t xpp; |
313
|
|
|
|
|
|
|
|
314
|
0
|
|
|
|
|
|
memset(&xpp, 0, sizeof(xpp)); |
315
|
0
|
|
|
|
|
|
xpp.flags = map->xpp->flags & ~XDF_DIFF_ALGORITHM_MASK; |
316
|
|
|
|
|
|
|
|
317
|
0
|
|
|
|
|
|
return xdl_fall_back_diff(map->env, &xpp, |
318
|
|
|
|
|
|
|
line1, count1, line2, count2); |
319
|
|
|
|
|
|
|
} |
320
|
|
|
|
|
|
|
|
321
|
|
|
|
|
|
|
/* |
322
|
|
|
|
|
|
|
* Recursively find the longest common sequence of unique lines, |
323
|
|
|
|
|
|
|
* and if none was found, ask xdl_do_diff() to do the job. |
324
|
|
|
|
|
|
|
* |
325
|
|
|
|
|
|
|
* This function assumes that env was prepared with xdl_prepare_env(). |
326
|
|
|
|
|
|
|
*/ |
327
|
0
|
|
|
|
|
|
static int patience_diff(mmfile_t *file1, mmfile_t *file2, |
328
|
|
|
|
|
|
|
xpparam_t const *xpp, xdfenv_t *env, |
329
|
|
|
|
|
|
|
int line1, int count1, int line2, int count2) |
330
|
|
|
|
|
|
|
{ |
331
|
|
|
|
|
|
|
struct hashmap map; |
332
|
|
|
|
|
|
|
struct entry *first; |
333
|
0
|
|
|
|
|
|
int result = 0; |
334
|
|
|
|
|
|
|
|
335
|
|
|
|
|
|
|
/* trivial case: one side is empty */ |
336
|
0
|
0
|
|
|
|
|
if (!count1) { |
337
|
0
|
0
|
|
|
|
|
while(count2--) |
338
|
0
|
|
|
|
|
|
env->xdf2.rchg[line2++ - 1] = 1; |
339
|
0
|
|
|
|
|
|
return 0; |
340
|
0
|
0
|
|
|
|
|
} else if (!count2) { |
341
|
0
|
0
|
|
|
|
|
while(count1--) |
342
|
0
|
|
|
|
|
|
env->xdf1.rchg[line1++ - 1] = 1; |
343
|
0
|
|
|
|
|
|
return 0; |
344
|
|
|
|
|
|
|
} |
345
|
|
|
|
|
|
|
|
346
|
0
|
|
|
|
|
|
memset(&map, 0, sizeof(map)); |
347
|
0
|
0
|
|
|
|
|
if (fill_hashmap(file1, file2, xpp, env, &map, |
348
|
|
|
|
|
|
|
line1, count1, line2, count2)) |
349
|
0
|
|
|
|
|
|
return -1; |
350
|
|
|
|
|
|
|
|
351
|
|
|
|
|
|
|
/* are there any matching lines at all? */ |
352
|
0
|
0
|
|
|
|
|
if (!map.has_matches) { |
353
|
0
|
0
|
|
|
|
|
while(count1--) |
354
|
0
|
|
|
|
|
|
env->xdf1.rchg[line1++ - 1] = 1; |
355
|
0
|
0
|
|
|
|
|
while(count2--) |
356
|
0
|
|
|
|
|
|
env->xdf2.rchg[line2++ - 1] = 1; |
357
|
0
|
|
|
|
|
|
xdl_free(map.entries); |
358
|
0
|
|
|
|
|
|
return 0; |
359
|
|
|
|
|
|
|
} |
360
|
|
|
|
|
|
|
|
361
|
0
|
|
|
|
|
|
first = find_longest_common_sequence(&map); |
362
|
0
|
0
|
|
|
|
|
if (first) |
363
|
0
|
|
|
|
|
|
result = walk_common_sequence(&map, first, |
364
|
|
|
|
|
|
|
line1, count1, line2, count2); |
365
|
|
|
|
|
|
|
else |
366
|
0
|
|
|
|
|
|
result = fall_back_to_classic_diff(&map, |
367
|
|
|
|
|
|
|
line1, count1, line2, count2); |
368
|
|
|
|
|
|
|
|
369
|
0
|
|
|
|
|
|
xdl_free(map.entries); |
370
|
0
|
|
|
|
|
|
return result; |
371
|
|
|
|
|
|
|
} |
372
|
|
|
|
|
|
|
|
373
|
0
|
|
|
|
|
|
int xdl_do_patience_diff(mmfile_t *file1, mmfile_t *file2, |
374
|
|
|
|
|
|
|
xpparam_t const *xpp, xdfenv_t *env) |
375
|
|
|
|
|
|
|
{ |
376
|
0
|
0
|
|
|
|
|
if (xdl_prepare_env(file1, file2, xpp, env) < 0) |
377
|
0
|
|
|
|
|
|
return -1; |
378
|
|
|
|
|
|
|
|
379
|
|
|
|
|
|
|
/* environment is cleaned up in xdl_diff() */ |
380
|
0
|
|
|
|
|
|
return patience_diff(file1, file2, xpp, env, |
381
|
0
|
|
|
|
|
|
1, env->xdf1.nrec, 1, env->xdf2.nrec); |
382
|
|
|
|
|
|
|
} |